Convert numbers to Words using VBA

'This sub is used to create words from numbers

Function WordNum(MyNumber As Double) As String
Dim DecimalPosition As Integer, ValNo As Variant, StrNo As String
Dim NumStr As String, n As Integer, Temp1 As String, Temp2 As String
If Abs(MyNumber) > 999999999 Then
WordNum = "Value too large"
Exit Function
End If
SetNums
' String representation of amount (excl decimals)
NumStr = Right("000000000" & Trim(str(Int(Abs(MyNumber)))), 9)
ValNo = Array(0, Val(Mid(NumStr, 1, 3)), Val(Mid(NumStr, 4, 3)), Val(Mid(NumStr, 7, 3)))
For n = 3 To 1 Step -1 'analyse the absolute number as 3 sets of 3 digits
StrNo = Format(ValNo(n), "000")
If ValNo(n) > 0 Then
Temp1 = GetTens(Val(Right(StrNo, 2)))
If Left(StrNo, 1) <> "0" Then
Temp2 = Numbers(Val(Left(StrNo, 1))) & " hundred"
If Temp1 <> "" Then Temp2 = Temp2 & " and "
Else
Temp2 = ""
End If
If n = 3 Then
If Temp2 = "" And ValNo(1) + ValNo(2) > 0 Then Temp2 = "and "
WordNum = Trim(Temp2 & Temp1)
End If
If n = 2 Then WordNum = Trim(Temp2 & Temp1 & " thousand " & WordNum)
If n = 1 Then WordNum = Trim(Temp2 & Temp1 & " million " & WordNum)
End If
Next n
NumStr = Trim(str(Abs(MyNumber)))
' Values after the decimal place
DecimalPosition = InStr(NumStr, ".")
Numbers(0) = "Zero"
If DecimalPosition > 0 And DecimalPosition < Len(NumStr) Then
Temp1 = " point"
For n = DecimalPosition + 1 To Len(NumStr)
Temp1 = Temp1 & " " & Numbers(Val(Mid(NumStr, n, 1)))
Next n
WordNum = WordNum & Temp1
End If
'MsgBox WordNum & " Only"
sht_Ex1.Range("D19") = WordNum & " Only"
If Len(WordNum) = 0 Or Left(WordNum, 2) = " p" Then
WordNum = "Zero" & WordNum
End If
End Function
Function GetTens(TensNum As Integer) As String
' Converts a number from 0 to 99 into text.
If TensNum <= 19 Then
GetTens = Numbers(TensNum)
Else
Dim MyNo As String
MyNo = Format(TensNum, "00")
GetTens = Tens(Val(Left(MyNo, 1))) & " " & Numbers(Val(Right(MyNo, 1)))
End If
End Function
Public Sub Number_Words()
    WordNum sht_Ex1.Range("C14")
End Sub